Question

corect Answer type
QUESTION 20:
A charge of 5C experiences a force of 5000 N when it is kept in a uniform electric field. What is the potential difference between two points
separated by a distance of 1 cm​

Answer 1

Answer:

10V

Explanation:

Electric field E=force / charge= V/d

=F/Q=5000/5=1000N/C

V=Ed=1000N/C*0.01m

10V.

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Answer 2

Charge: 5c

Force: 5000N

Distance: 0.01m

V: ?

t=

q

Force

​

=

5

5000

​

=1000V

also, E=

dr

dv

​

⇒dv=E(dr)=1000

100

(0.01)

​

m

v=10V

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