Question

coressponding sides of<br /> of two similar triangles are 3cm and 4cm if area are bigger triangle is 48 find the area of smaller Triangle

Answer 1

Solution :

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We know the theorem :

The ratio of the areas of two similar

triangles is equal to the ratio of the

squares of their corresponding

sides .

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Here ,

Let A1 , A2 are areas of two similar

triangles and s1, s2 are their

corresponding sides respectively ,

s1 = 3 cm , s2 = 4cm,

A1 = ? , A2 = 48 cm²

Now ,

A1/A2 = ( s1/s2 )²

=> A1/48 = ( 3/4 )²

=> A1 = ( 9 × 48 )/16

= 9 × 3

= 27

Therefore ,

Area of smaller triangle = A1 = 27 cm²

•••••

Answer 2

Step-by-step explanation:

Corresponding sides of two similar triangles are 3cm and 4cm . If the area of the larger triangle is 48cm^2 , find the area of the smaller triangle.

Missing: br ‎|

Let A1 and A2 be the area of triangle and S1 and S2 be the their corresponding sides.By the property of area of two similar triangle,Ratio of area ...

the larger triangle is 48cm

2

,

Let A

1

and A

2

be the area of triangle and S

1

and S

2

be the their corresponding sides.

By the property of area of two similar triangle,

Ratio of area of both triangles = (Ratio of their corresponding sides)

2

A

2

A

1

=(

S

2

S

1

)

2

48

A

1

=(

4

3

)

2

⇒A

1

=48×

16

9

=27cm

2