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0
Answer:
let
y
=
1
x
+
4
the denominator of y cannot be zero as this would make
y undefined. Equating the denominator to zero and
solving gives the value that x cannot be
solve
x
+
4
=
0
⇒
x
=
−
4
←
excluded value
domain
x
∈
R
,
x
≠
−
4
(
−
∞
,
−
4
)
∪
(
−
4
,
∞
)
←
in interval notation
to find the range, rearrange making x the subject
y
(
x
+
4
)
=
1
x
y
+
4
y
=
1
x
y
=
1
−
4
y
x
=
1
−
4
y
y
y
=
0
←
excluded value
range
y
∈
R
,
y
≠
0
(
−
∞
,
0
)
∪
(
0
,
∞
)
graph{1/(x+4) [-10, 10, -5, 5]}
Exact Form:
35
2
Decimal Form:
17.5
Mixed Number Form:
17
1
2
x = 9, y = 4 is a solution of the linear equation
Answered by
0
Answer:
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