Question

correct ans will be marked as brainliest. proof For all sets A, B and C, A- (B-C) = (A -B)-C​

Answer 1

Answer:

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Answer 2

Answer:

Given: AB = AC and ∆ABC circumscribe a circle with the circle touching the side AB at R, AC at Q and BC at P.

To Prove: P bisects the side of the triangle, BC.

⇒ BP = PC

Proof: ∵, RB and BP are tangents to the circle from the same point. ⇒ BP = BR …(i)

QC and CP are tangents to the circle from the same point. ⇒ QC = CP …(ii)

Also, RA and AQ are tangents to the circle from the same point. ⇒ AQ = AR …(iii)

Adding equations (i), (ii) and (iii), we get

BP + QC + AQ = BR + CP + AR

⇒ (AQ + QC) + BP = (AR + BR) + CP

⇒ AC + BP = AB + CP

⇒ BP = CP [∵, BP = CP]