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The LCM and HCF of two numbers are 12 and 72, and the addition of two numbers is 60. What are the numbers?
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Let the two numbers be x and y.
We know that.. product of two numbers = HCFx LCM.
Therefore XY= 12 x 72= 864….(1)
According to given condition, their sum is 60
Therefore x+y = 60……….(2)
We know that
(x-y)² =(x+y)² -4xy
Substitute values from 1 & 2
(X-y)² = 3600–4x864=144
X-Y =√144= 12…(3)
By solving 2 and 3
We get x=36 and y=24.
24 is the correct answer..
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