Question

correct answer of this question

Answer 1

Answer:

Step-by-step explanation:

given: PA and PB are 2 tangents,O is the centre of the circle.

NOW,

In triangles ACP and BCP,

AP = BP

so triangle ABP is isosceles.

angle PAC=angle PBC

side CP is common.

therefore triangles ACP and NO are congruent.(S.S.S axiom of congruency)

angle ACP = angle BCP.

BUT

Angles ACP+BCP=180 degrees.

SO, ACP=BCP=90degrees.............(i)

AC=BC(cpct)......................................(ii)

from(i) and(ii),

OP is the perpendicular bisector of AB