Question

correct answer pls

I'll mark u as brainliesttttt​

Answer 1

Answer:

$\huge\red{ANSWER}$

14,24304 ₹

Step-by-step explanation:

$\huge\red{diameter \: of \: roller}$

$\pi {r}^{2} \times h \\ \\ 3.14 \times 3600 \times 84 \\ \\ 949536c {m }^{2} \\ \\ convert \: it \: into \: metre \\ 9495.36 {m}^{2} \times 500 \times 30paice \\ 142430400paise \\ 1424304 \: rupey$

$\huge\red{make}\:\huge\blue{me}\: \orange{brainliest}$

Answer 2

REQUIRED ANSWER ✍️:-

₹475.20

SOLUTION ⭐:-

Height of roller= 120 CM

Diameter of its base= 84cm

∴ The radius of its base=

$\frac{84}{2}cm = 42cm$

∴ Curved surface area of the roller=

$2\pi \: rh$

$= (2 \times \frac{22}{7} \times 42 \times 120) {cm}^{2}$

$= 31680 {cm}^{2}$

Area covered in one revolution = Curved surface area of roller

∴ Area covered in 500 revolutions

= Curved surface area of roller×500

= (31680 × 500) cm²

= 15840000 cm²

= 15840000 / 10000 m² (∵ 1m² =10000cm²)

= 1584m²

Now, cost of levelling 1m²= 30 paise

∴Cost of levelling 1584m²

= (1584×30) paise

=47520 paise

=₹475.20

HOPE IT HELPS ✨

THANK YOU ❤️❣️

I study at DAV BALURGHAT AND THIS IS ALSO A QUESTION FROM WORKSHEET ☺️