Question

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If the sum of the zeroes of the polynomial P(x) = 3k^2 + (2k + 1)x-k+5 is equal to the product of the zeroes, then, find the value of k.

The Answer is k= -6

So plz solve it in steps​

Answer 1

P(x) = 3k^2 + (2k + 1)x-k+5

P(x)=3(-6)^2+(2(-6)+1)x-(-6)+5

P(x)=3(12)+(-12+1)x+6+5

P(x)=36+(-11)x+11

P(x)=36-11x+11

P(x)=25-11x

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Answer 2

Answer:

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