Question

Correct answer will be marked as brainliest ​

Answer 1

Answer:

$=\frac{12 {f}^{2} - 3 {e}^{2} }{10f - 5e} \div \frac{6e + 12f}{15 {f}^{2} }$

$= \frac{3(4 {f}^{2} - {e}^{2} ) }{5(2f - e)} \times \frac{15 {f}^{2} }{6(e + 2f)}$

$=\frac{3 {f}^{2}(4 {f}^{2} - {e}^{2} )}{2(2f - e)(2f + e)}$

$=\frac{12 {f}^{4} - 3 {f}^{2} {e}^{2} }{2(( {2f}^{2}) - {e}^{2}) }$

$=\frac{12 {f}^{4} - 3 {f}^{2} {e}^{2} }{2(4 {f}^{2} - {e}^{2}) }$

$=\frac{12 {f}^{4} - 3 {f}^{2} {e}^{2} }{8 {f}^{2} - 2 {e}^{2} }$

Answer 2

$\mathsf{\begin{gathered} =\frac{12 {f}^{2} - 3 {e}^{2} }{10f - 5e} \div \frac{6e + 12f}{15 {f}^{2} } \\ \end{gathered}} \\ \\ \mathsf{\begin{gathered}= \frac{3(4 {f}^{2} - {e}^{2} ) }{5(2f - e)} \times \frac{15 {f}^{2} }{6(e + 2f)} \\ \end{gathered} } \\ \\ \mathsf{\begin{gathered} =\frac{3 {f}^{2}(4 {f}^{2} - {e}^{2} )}{2(2f - e)(2f + e)} \\ \end{gathered}} \\ \\ \mathsf{\begin{gathered} =\frac{12 {f}^{4} - 3 {f}^{2} {e}^{2} }{2(( {2f}^{2}) - {e}^{2}) } \\ \end{gathered}} \\ \\ \mathsf{\begin{gathered}=\frac{12 {f}^{4} - 3 {f}^{2} {e}^{2} }{2(4 {f}^{2} - {e}^{2}) } \\ \end{gathered} }\\ \\ \mathsf{\begin{gathered}=\frac{12 {f}^{4} - 3 {f}^{2} {e}^{2} }{8 {f}^{2} - 2 {e}^{2} } \\ \end{gathered}}$