Question

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Answer 1

Answer:

L.H.S is

secA-tanA/(secA+tanA)(sec A-tanA)

=secA-tanA/sec^2A-tan^2A

=secA-tanA/1

as sec&2A-tan^2A=1

=secA-tanA

R.H.S is

secA-tanA

Therefore L.H.S=R.H.S

Answer 2

Answer:

$\frac{1}{ \sec(a) + \tan(a) } = \sec(a) - \tan(a) \\ = from \: lhs \\ = \frac{1}{ \sec(a) + \tan(a) } \times \frac{ \sec(a) - \tan(a) }{ \sec(a) - \tan(a) } \\ = \frac{ \sec(a) - \tan(a) }{ {sec}^{2} a - {tan}^{2}a } \\ = \sec(a) - \tan(a) \\ prooved$

PROOVED

Step-by-step explanation:

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