Question

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Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Value\:of\:x=24.065\:and\:-265.065}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies {x}^{2} + 241x - 6380 = 0 \\ \\\red{\underline \bold{To \: Find :}} \\ \tt: \implies Value \: of \: x = ?$

• According to given question :

$\tt \circ \: a = 1 \\ \\ \tt \circ \: b = 241 \\ \\ \tt \circ \:c = 6380 \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies D = {b}^{2} - 4ac \\ \\ \tt: \implies D= {(241)}^{2} - 4 \times 1 \times ( - 6380) \\ \\ \tt: \implies D= 58081 +25520 \\ \\ \tt: \implies D= 83601 \\ \\ \tt: \implies x = \frac{ - b \pm \sqrt{D }}{2a} \\ \\ \tt: \implies x = \frac{ - 241 \pm \sqrt{83601} }{2 \times 1} \\ \\ \tt \circ \: \sqrt{83601} \approx 289.13 \\ \\ \tt: \implies x = \frac{ - 241 \pm289.13}{2} \\ \\ \tt: \implies x = \frac{ - 241 + 289.13}{2} \\ \\ \tt: \implies x = \frac{48.13}{2} \\ \\ \green{\tt: \implies x = 24.065} \\ \\ \tt: \implies x = \frac{ - 241 - 289.13}{2} \\ \\ \tt: \implies x = \frac{ - 530.13}{2} \\ \\ \green{\tt: \implies x = - 265.065}$

Answer 2

$</p><p>\tt{\orange{\huge{Hello!!! }}}$

Solving By The Sridharacharya Method,

$\tt{ \red{x \: = \dfrac{ - b \: + \sqrt{ {b}^{2} - 4ac } }{2a} }}$

Solving we get the two values of X as

X = 24.065

X = -256.065