Math, asked by yourgamingmate, 1 month ago

CORRECT ANSWER WILL BE MARKED AS BRAINLIEST
for what value of p x=2,y=3 is a solution of (p+1)x-(2p+3)y-1=0 and write the equation .how many solutions of this equation are possible? Is this line passes through point (-2,3)?give justification

Answers

Answered by someone1376
0

Answer:

explanation:

According to question

X=2,y=3

(p+1)2-(2p+3)3-1=0

2p+2-6p-9-1=0

2p-6p-9-1+2=0

-4p-10+2=0

-4p-8=0

-4p=8

p=8/-4=-2

p=-2

Next

Put the value of p=-2

(-2+1)2-(2×-2+3)3-1=0

(-1)2-(-1)3-1=0

-2+3-1=0

-3+3=0

0=0

Answered by FlamingThunderGod
0

explanation:

According to question

X=2,y=3

(p+1)2-(2p+3)3-1=0

2p+2-6p-9-1=0

2p-6p-9-1+2=0

-4p-10+2=0

-4p-8=0

-4p=8

p=8/-4=-2

p=-2

Next

Put the value of p=-2

(-2+1)2-(2×-2+3)3-1=0

(-1)2-(-1)3-1=0

-2+3-1=0

-3+3=0

0=0

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