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for what value of p x=2,y=3 is a solution of (p+1)x-(2p+3)y-1=0 and write the equation .how many solutions of this equation are possible? Is this line passes through point (-2,3)?give justification
Answers
Answered by
0
Answer:
explanation:
According to question
X=2,y=3
(p+1)2-(2p+3)3-1=0
2p+2-6p-9-1=0
2p-6p-9-1+2=0
-4p-10+2=0
-4p-8=0
-4p=8
p=8/-4=-2
p=-2
Next
Put the value of p=-2
(-2+1)2-(2×-2+3)3-1=0
(-1)2-(-1)3-1=0
-2+3-1=0
-3+3=0
0=0
Answered by
0
explanation:
According to question
X=2,y=3
(p+1)2-(2p+3)3-1=0
2p+2-6p-9-1=0
2p-6p-9-1+2=0
-4p-10+2=0
-4p-8=0
-4p=8
p=8/-4=-2
p=-2
Next
Put the value of p=-2
(-2+1)2-(2×-2+3)3-1=0
(-1)2-(-1)3-1=0
-2+3-1=0
-3+3=0
0=0
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