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siddhartharao77:
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Answered by
0
Using the Direct method
Mean = sum of fixi ÷ sum of fi
By solving, sum of fixi = 518+18p
and sum of fi = 30+p putting the values
17.45=518+18p ÷ 30+p
523.5+17.45p=518+18p
523.5-518=18p-17.45p
5.5=0.55p
so, p=5.5÷0.55
p=10
Mean = sum of fixi ÷ sum of fi
By solving, sum of fixi = 518+18p
and sum of fi = 30+p putting the values
17.45=518+18p ÷ 30+p
523.5+17.45p=518+18p
523.5-518=18p-17.45p
5.5=0.55p
so, p=5.5÷0.55
p=10
Answered by
3
Xi = 15,16,17,18,19,20.
Fi = 3,8,10,P,5,4.
Now,
∑FiXi = 45, 128, 170, 18P, 95, 80.
= 518 + 18P.
∑Fi = 30 + P
Given Mean = 17.45.
17.45 = 518 + 18P/30 + P
523.5 + 17.45P = 518 + 18P
17.45P - 18P = 518 - 523.5
-0.55P = -5.5
P = 5.5/0.55
P = 10.
Therefore the value of P = 10.
Hope this helps!
Fi = 3,8,10,P,5,4.
Now,
∑FiXi = 45, 128, 170, 18P, 95, 80.
= 518 + 18P.
∑Fi = 30 + P
Given Mean = 17.45.
17.45 = 518 + 18P/30 + P
523.5 + 17.45P = 518 + 18P
17.45P - 18P = 518 - 523.5
-0.55P = -5.5
P = 5.5/0.55
P = 10.
Therefore the value of P = 10.
Hope this helps!
Any doubts. Ask me. Gud luck!
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