Question

correct answer will surely get brillianist

explanation needed​

Answer 1

Answer:

3π s

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Answer 2

$\large \rm {\underbrace{\underline{➻Elucidation:-}}}$

$\sf \pink {\underline{\underline{Provided\: that:-}}}$

$\sf \mapsto {Length\: of\: the\: pendulum(l)=10m}$

$\sf \mapsto {Acceleration\: due\: to\: gravity(g)=10m/s^{2}}$

$\sf \blue {\underline{\underline{To\: determine:-}}}$

$\sf \mapsto {Time\: period\: of\: the\: pendulum(t)=?}$

$\sf \orange {\underline{\underline{We\: know:-}}}$

$\sf \mapsto {\boxed{Time\: period(t)=2π{\sqrt{\frac{l}{g}}}}}$

➻Supplanting the given values,

$\sf \mapsto {Time\: period(t)=2π{\sqrt{\frac{10}{10}}}}$

$\sf \mapsto {Time\: period(t)=2π{\sqrt{\frac{\cancel{10}}{\cancel{10}}}}}$

$\sf \mapsto {Time\: period(t)=2π{\sqrt{1}}}$

$\sf \mapsto {Time\: period(t)=2π×1}$

$\sf \implies \green {\fbox{Time\: period(t)=2πs}}$

$\sf \purple {\underline{\underline{Henceforth,}}}$

➻"Option-4" is the correct option.

➻The time period of the simple pendulum is 2πseconds respectively.