Question

Correct increasing order of no. Of sigma and pi bonds in h2s2o6 ,h2so3,h2so5

Answer 1

h2so3, h2so5, h2so6.......

Answer 2

Answer:

Decreasing order of number of $\pi-bond$ is $H_{2}S_{2}O_{6} > H_{2}SO_{3} > H_{2}SO_{5}$

Increasing order of number of $\pi$ bond is $H_{2}SO_{3} < H_{2}SO_{5} < H_{2}S_{2}O_{6}$

Explanation:

Given: Chemical compounds

To find: Correct increasing order of no. of sigma and pi bonds

Explanation:

Lewis structure -

• Pair of bonded electrons is by means of a dash (-) usually called a bond
• Lone pairs or non-bonded electrons are represented by dots
• Electrons represented in the last shell of atoms are called valence electrons.
• wherein
• In $H_{2} S_{2} O_{6}$the number of $\pi bond$ is 4
• In $H_{2}SO_{3}$ the number of $\pi - bond$ is 1 and in$H_{2}SO_{5}$number of $\pi- bond$ is 3

Decreasing order of number of $\pi-bond$ is $H_{2}S_{2}O_{6} > H_{2}SO_{3} > H_{2}SO_{5}$

Increasing order of number of $\pi$ bond is $H_{2}SO_{3} < H_{2}SO_{5} < H_{2}S_{2}O_{6}$