Correct order of bond angles in nh3 pcl3 bcl3
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first calculate hybridisation of central atom
then subtract hybridisation and no. of surronding atoms
which will give no. of lone pairs
we know that bond angle inversely proportional to lone pairs
for nh3
we have 1 lone pair
for pcl4
we have 1 lone pair
for bcl3
we have 0 lone pair
and we can see same lone pairs for both nh3 and pcl4
in this case main atom is same you should take atoms which has less electro negativity
which means h has less electro negativity means it has more bond angle
so the final order is bcl3,nh3 and pcl4
note this is increasing bond order
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