Question

Correct order of covalent character of
given halides is
O
AlF3 > AlCl3 > AlBrz
O
AlCl3 > AlBr3 > AlF3
O
AlF3 > AlBrz > A1C13
O
AlBr3 > AICI: > AlF3​

Answer 1

Answer:

option b Alcl3 Albr2 Alg3

Answer 2

The correct order of covalent character is

$AlBr_3>AlCl_3>AlF_3$.

• As the electronegativity difference between the metal that is Al and halogen decreases the covalent character increases.
• Among halogens, F is the most electronegative element and Br is the least electronegative element.
• So, the electronegativity difference between Al and F is highest and it has the lowest covalent character. Again the electronegativity difference between Al and Br is the lowest and it has the highest covalent character.
• Thus, the order of covalent character is-
• $AlBr_3>AlCl_3>AlF_3$