Question

Correct order of ionic radius for the following isoelectronic species is
(Atomic number of Al = 13, Mg = 12, Na = 11, F = 9,0 = 8, N = 7)
OA.? Arts
> Mg+2 > Na+ > TFT
>re- > Po-2 > 'n-s
B.? Ai+3 <rmg+2 </Na+ < Timo 2 KINS
C.? Aits
-
"Mg+2
7 Na+ KrF Tro-2 = TN-3
OD. Aits = 7Mg+2 = ''Nat FIF
"Na+ = rf- = ro-2 = TN-3​

Answer 1

Explanation:

ANSWER

All the species are iso-electronic (10e

−

)

For iso-electronic species more the positive change, smaller the ionic radii.

For iso-electronic species more negative change, bigger the ionic radii

Hence the order is Mg

2+

<Na

+

<F

−

<O

2−

Hence, the correct option is B.