Chemistry, asked by syedaafshajabeen2003, 4 days ago

Correct order of limiting molar conductivity of given ions in water at 298K is K^(+)>Na^(+)>Mg^(2+) Mg^(2+)>K^(+)>Na^(+) Mg^(2+)>Na^(+)>K^(+) Na^(+)>K^(+)>Mg^(2+)​

Answers

Answered by khushisharma4508
0

Answer:

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Explanation:

Smaller is the size of cation, greater will be the mobility and hence, the conductivity. The size of the cation increases as we move from Li+ to Rb+. Hence, the conductivity should decrease. However, in aqueous solution, due to very small size of Li+, it is strongly hydrated and hence, its effective hydrated size is greater than that of Rb+.

So, the correct order of increasing ionic conductance is as follows:

Li+<Na+<K+<Rb+

Hence, option A is correct.

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