Correct set of quantum numbers defining the highest energy electron in scandium (I) ion is
(A) n=3,1 = 1, m=0,s=-1/2
(B) n=3,1 = 0, m=0,s=-1/2
(C) n=4,1 = 0, m = 0,s=+1/2
(D) n=3,1 = 2, m=2,s = +1/2
Answers
Answered by
6
Answer:
Pls mark me as brainliest
Explanation:
Energy of an orbital = n + l
A) Energy = 3 + 1 = 4
B) Energy = 3 + 0 = 3
C) Energy = 4 + 0 = 4
D) Energy = 3 + 2 = 5
Similar questions