Correct set of quantum numbers of the last electrons of Na+ ion
Answers
Configuration of Na is [Ne]3s1
configuration of Na+ ion 1s^2s^22p^6
so set of quantum numbers will be
n=2,l=1,m=-1,0,+1,s=-1/2 or +1/2
Answer:
3, 0, 0, and +1/2or−1/2.
Explanation:
An atom is absolutely defined through the 4 quantum numbers: predominant quantum wide variety (n), azimuthal quantum wide variety (l), magnetic moment ( ml), and spin quantum wide variety ms.
Let’s first write down the subshell digital configuration of the sodium atom. We understand that the atomic wide variety of sodium is 11. So, the subshell digital configuration is as follows:
Na = 1s22s22p63s1
According to the Aufbau principle, we understand that electrons are stuffed in orbitals of an atom consistent with their electricity. The electron having better electricity might be stuffed last. So, we understand that the electron withinside the 3s orbital has the very best electricity.
Now we should write the quantum numbers for this electron.
(1) Principal quantum wide variety (n):
The predominant quantum wide variety describes the wide variety of shells. Here, we're inquisitive about the very best electricity degree electron. In sodium, the very best electron enters withinside the 3s orbital. Therefore the predominant quantum wide variety is withinside the 0.33 shell,(n = 3).
(2) Azimuthal quantum wide variety (l):
The orbital momentum quantum wide variety (l) determines the form of the subshell. The ‘l’ cost is much less than the predominant quantum wide variety(n−1). For sodium, (n = 3)consequently the ‘l’ cost is calculated as:
l= (n−1)=3−1=2l= (n−2)=3−2=1l= (n−1)=3−3=0
Therefore, the azimuthal quantum wide variety (l) for the 0.33 shell of sodium atom is 0, 1, 2.
Here,
l=0 ⇒ sl=1 ⇒ pl=2 ⇒ d
Since the very best shell electron of sodium is withinside the 3sshell, consequently the ‘l’ cost for 3s an electron is l=0
(3) Magnetic quantum wide variety (ml) :
The quantum wide variety describes the orbitals and their orientation withinside the subshell. These values rely on the azimuthal quantum wide variety. For a certain ‘l’ cost the (ml) values variety from−l to +l. Therefore, the above ‘l’ values, the (ml) values for the 0.33 shell of sodium is:
ml= ± lFor l=2 , ml = ±2 or −2 , +2For l=1 , ml = ±1 or −1 , +1For l=0 , ml = 0 ∴ ml = −2 , −1 , 0 , +1 , +2
Therefore, for (n = 3) the magnetic quantum numbers are: −2 , −1 , 0 , +1 , +2
Since the sodium has the l=0 , hence the magnetic quantum wide variety for 3s an electron is (ml)Na= 0
Since the 3s electron of the sodium
(4) Electron spin quantum wide variety ( ms):
The electron spin quantum wide variety ms does now no longer rely on any other quantum wide variety. It famous the route of the electron spin. The spin has a cost of +1/2 or −1/2. That means, whilst the ms cost is positive, the electron has an top spin, and whilst a bad electron has down spin.
Therefore, an electron withinside the 0.33 shell of an electron might also additionally be ‘spin up’ or ‘spin down’.
(ms)Na = ± 12
So, the quantum numbers for the electron of sodium atom having the very best electricity are 3, 0, 0, and +1/2or−1/2.
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