Question

Correct Solutions only

If addition of five consecutive numbers is 270. Calculate the sum of the 4th and 5th Number.

Answer with good solution is required

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Answer 1

$\large{\green{\bold{\underline{Let:}}}}$

$\sf \: The \: five \: numbers \: be \: x, \: x+1, \: x+2, \: x+3 \: and \: x+4$$\large{\red{\bold{\underline{Then:}}}}$

$\large{\orange{\bold{\underline{According \: To \: Question:}}}}$

$\rightarrow \sf \: x + (x+1) + (x+2) + (x+3) + (x+4) = 270 \\ \\ \rightarrow \sf \: x + x+1 + x+2 + x+3 + x+4 = 270 \\ \\ \rightarrow \sf \: 5x + 10 = 270 \\ \\ \rightarrow \sf \: 5x = 270 - 10 \\ \\ \rightarrow \sf \: 5x = 260 \\ \\ \rightarrow \sf \: x = \frac{ \cancel260}{ \cancel5} \\ \\ \rightarrow \sf \: x = 52$

$\large{\red{\bold{\underline{Then:}}}}$$\sf \: Numbers \: are \: 52, \: 52+1, \: 52+2, \\ \sf \: 52+3 \: and \: 52+4.$

$\large{\blue{\bold{\underline{Finally:}}}}$$\sf \: Five \: consecutive \: numbers \: are \: 52, \: 53, \: 54, \\ \sf \: 55 \: and \: 56.$

$\large{\pink{\bold{\underline{But:}}}}$

$\sf \: We \: need \: to \: find \: addition \: of \: 4th \\ \sf \: and \: 5th \: number.$$\rightarrow \sf \: 55 + 56 \\ \rightarrow \sf \: 111$

$\large{\green{\bold{\underline{Hence:}}}}$

$\underline{ \underline{ \sf \: The \: required \: Answer \: is \: 111.}}$

Answer 2

Given:-

addition of five consecutive numbers is 270.

To find:-

the sum of the 4th and 5th Number.

Solution:-

let the 5 consecutive no.s be x , x+1 , x+2 , x+3 and x+4.

According to the question

x + x +1 + x + 2 + x + 3 + x + 4 = 270

5x + 10 = 270

5x = 270 - 10

x = 260/5

x = 52.

So 4th no. = x + 3 = 52 + 3 = 55

and 5th no. = x + 4 = 52 + 4 = 56.

So the sum of 4th and 5th no.

= 55 + 56

= 109.( ans)

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