Question

corresponding ne.
Practice set 1.1
. Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height
is 6. Find the ratio of areas of these triangles.​

Answer 1

♦ Given :- Let The triangle be ∆ABC and ∆PQR.

In ∆ABC,

Base of ∆ABC is BC = 9cm

Altitude of ∆ABC is AE = 5cm

In ∆PQR,

Base is QR = 10cm

Altitude is PM = 6cm

♦ To Find :- Ratio of Area of ∆ABC and ∆PQR

♦ Solution :-

Find the area of first triangle :

Base of triangle = 9cm

Height of triangle = 5cm

Area of triangle = 1 / 2 × base × height

⇒ 1 / 2 × 9 × 5

⇒ 45 / 2

Find the area of second triangle :

Base of triangle = 10 cm

Height of triangle = 6 cm

Area of triangle = 1 / 2 × base × height

⇒ 1 / 2 × 10 × 6

⇒ 30 cm

Find the ratio of the areas of both the triangles ;

Ratio = Area of first Δ / Area of 2nd Δ

Ratio = 45 / 2 × 1 / 30

Ratio = 3 / 4

Ratio = 3 : 4

Hence, Ratio of Area of ∆ABC to ∆PQR is 3:4

Hope this helps...

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Answer 2

Answer:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

∴A(△ABC)/A(△PQR)

=AB×BC/PQ×QR

=5×9/6×10

=3/4