Corresponding sides of two similar triangles are 3 cm and 4 cm if the area of the larger triangle is 48 CM square find the area of the similar Triangle
Answers
Answered by
1
Since both triangles are equal, therefore,
Area of required triangle=3^2/4^2*48
=9/16*48
=27cm^2
Answered by
4
Hi,
Answer: ar(∆ABC)= 27 sq-cm
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Solution:
➖➖➖➖
Let the given triangle are ∆ ABC and ∆XYZ
and ∆XYZ is larger one
given that
∆ ABC ~ ∆XYZ
So
AB/XY = BC/YZ=AC/XZ
area of ∆ XYZ/area of ∆ABC= (XY)^2/(AB)^2
48/area of ∆ABC = 16/9
area of ∆ABC = 48(9)/16
= 432/16
= 27 sq-cm
Hope it helps you.
Answer: ar(∆ABC)= 27 sq-cm
➖➖➖
Solution:
➖➖➖➖
Let the given triangle are ∆ ABC and ∆XYZ
and ∆XYZ is larger one
given that
∆ ABC ~ ∆XYZ
So
AB/XY = BC/YZ=AC/XZ
area of ∆ XYZ/area of ∆ABC= (XY)^2/(AB)^2
48/area of ∆ABC = 16/9
area of ∆ABC = 48(9)/16
= 432/16
= 27 sq-cm
Hope it helps you.
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