Question

*Corresponding sides of two similar triangles are in the ratio of 2:3. If the area of small triangle is 48 sq.cm, then the area of large triangle is ………..*

1️⃣ 230 sq.cm.
2️⃣ 106 sq.cm
3️⃣ 107 sq.cm.
4️⃣ 108 sq.c​

Answer 1

Given :- Corresponding sides of two similar triangles are in the ratio of 2:3. If the area of small triangle is 48 sq.cm, then the area of large triangle is ………..

1) 230 sq.cm.

2) 106 sq.cm

3) 107 sq.cm.

4) 108 sq.cm.

Solution :-

we know that,

• Ratio of areas of two similar triangles = ratio of square of their corresponding sides .

so,

→ small ∆ Area / large ∆ Area = (2/3)²

→ 48 / large ∆ Area = 4 / 9

→ large ∆ Area * 4 = 48 * 9

→ large ∆ Area = 12 * 9

→ large ∆ Area = 108 sq. cm. (4) (Ans.)

Hence, area of large triangle will be 108 sq. cm.

Learn more :-

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angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

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