Corresponding sides of two similar triangles are in the ratio 1 : 3. If the area of the smaller triangle in 40 
, find the area of the larger triangle.
Answers
Answer:
The area of the larger ∆ is 360 cm²
Step-by-step explanation:
Given:
Let the Smaller triangle be ΔABC & bigger triangle be ΔPQR and the corresponding sides be BC & QR
ΔABC ~ ΔPQR.
Area of ΔABC = 40 cm².
BC : QR = 1 : 3
ar(ΔABC)/ar( ΔPQR) = (BC/QR)²
[The ratio of area of two similar triangles is equal to the ratio of squares of their corresponding sides.]
40 /ar( ΔPQR) = (1/3)²
40/ar( ΔPQR) = 1/9
ar( ΔPQR) = (9 × 40)
ar( ΔPQR) = 360 cm²
Hence, the area of the larger ∆ is 360 cm²
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Answer:
Heymate⌋
✨ Here's ur answer
➡️ Let the area of larger triangle be x,
Then,
✨ \frac{area \: of \: triangle \: 1}{area \: of \: triangle \: 2} = (\frac{1st \: \: t \: length}{2nd \: t \: length} )^{2}
areaoftriangle2
areaoftriangle1
=(
2ndtlength
1sttlength
)
2
✨ \frac{48}{x} = ( \frac{2}{3} )^{2}
x
48
=(
3
2
)
2
✨X= \frac{ 48 \times 9 }{4}
4
48×9
\underline{Answer =108cm}^{2}
Answer=108cm
2
˙·٠•●♥[ Hope it helps you ]♥●•٠·˙