Corresponding sides of two triangles are in the ratio 2 : 3. If the area of the smaller triangle is 48 , determine the area of the larger triangle.
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Answered by
1
Answer:
The area of the larger ∆ is 108 cm²
Step-by-step explanation:
Given:
Let the Smaller triangle be ΔABC & bigger triangle be ΔPQR and the corresponding sides be BC & QR
ΔABC ~ ΔPQR.
Area of ΔABC = 48 cm².
BC : QR = 2 : 3
ar(ΔABC)/ar( ΔPQR) = (BC/QR)²
[The ratio of area of two similar triangles is equal to the ratio of squares of their corresponding sides.]
48 /ar( ΔPQR) = (2/3)²
48/ar( ΔPQR) = 4/9
ar( ΔPQR) = (9 × 48)/4
ar( ΔPQR) = 9 × 12
ar( ΔPQR) = 108 cm²
Hence, the area of the larger ∆ is 108 cm²
HOPE THIS ANSWER WILL HELP YOU ..
Answered by
10
•Let the area of larger traingle be "x"
X=108 cm^2
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