Math, asked by seemagupta93308, 4 months ago

cos 0 =1/ 2
Find the value of 2 seco/
1+ tan²o​

Answers

Answered by vijaygehlot987
0

Answer:

1

sec o=2

1+tan^2 o=sec^2 o

4/2^2=1

Attachments:
Answered by Vibhutomer
1

Answer:

1

Step-by-step explanation:

cos 0 = 1/2 = B/H

P^2 = H^2 - B^2

P^2 = 4 - 1

P = √3

2 sec 0 / 1+tan^2 0

2 × 2/1 / 1 + 3/1

4/4

= 1

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