cos 0 =1/ 2
Find the value of 2 seco/
1+ tan²o
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Answered by
0
Answer:
1
sec o=2
1+tan^2 o=sec^2 o
4/2^2=1
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Answered by
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Answer:
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Step-by-step explanation:
cos 0 = 1/2 = B/H
P^2 = H^2 - B^2
P^2 = 4 - 1
P = √3
2 sec 0 / 1+tan^2 0
2 × 2/1 / 1 + 3/1
4/4
= 1
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