cos 0
(1 + cos 0) (1 - cos 0)
In a right angle triangle ABC, right angle is at B, if tan A =
then find the value of
(1) sin A cos C + cos A sin C
(ii) cos A cos C -sin A sin C
a
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sorry I didn't know
Step-by-step explanation:
mark me as brilliant
Answered by
1
Answer:
- sinA sin(90 - C) + cos A cos(90 - C) =
- cos A cos C - sin A sin C = cos (A+B)
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