Question

cos 0 = 5/13 find sin 0 ​

Answer 1

Answer:

cos∅=5/13=b/h

now we find the perpendicular.

h²=b²+p² (p= perpendicular

(13)²=5²+ p² h= hypotenuse

169=25+ p² b= base)

169-25= p²

144 = p²

✓144 = p

12 = p

sin∅=p/h

=12/13