Question

cos 0 + root 2 sin 45 + sin A = 3 then A=​

Answer 1

The value of A = 90°

Given:

cos 0 + √2 sin 45 + sin A = 3

To find:

The value of A

Solution:

Given that cos 0 + root 2 sin 45 + sin A = 3

From trigonometric table

     ⇒ cos 0° = 1

     ⇒ sin 45° = 1/√2

⇒ Given expression can be written as

⇒ 1 + √2 (1/√2)  + sin A = 3  

⇒ 1 + 1 + sin A = 3

⇒ 2 + sin A = 3

⇒ sin A = 3 - 2

⇒ sin A = 1

As we know from trigonometric table

    ⇒ sin 90° = 1

⇒ sin A = sin 90°

Therefore, the value of A = 90°

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Answer 2

Answer:

The answer to the given question is 90°

which is

$\frac{\pi}{2}$

Step-by-step explanation:

Given:

$\cos(0) + \sqrt{2} \sin(45) + \sin(a) = 3$

To find :

we have to find the value of A.

Solution:

As we know from the trigonometric table the value of terms in the question can be obtained as follows.

cos value will be

$\cos(0) = 1$

sin value will be obtained as

$\sin(45) = \frac{1}{ \sqrt{2} }$

let the sin A be x.

Then, on substituting the value in the given expression we get the values as

$1 + \sqrt{2 }\times \frac{1}{ \sqrt{2} } + x = 3$

Both the root values will get cancelled.

$1 + 1 + x = 3 \\ 2 + x = 3 \\ x = 3 - 2 \\ = 1$

The value of x is 1.

which means the value of sin A =1.

From the trigonometric table, we have to find for which value of sin, we get the resultant value as 1.

$\sin(90) = 1$

Therefore, the value we found is 90°.

which is

$\frac{\pi}{2}$

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