Question

(cos(0)+sin(45)+sin(30))×(sin(90)−cos(45)+cos(60))

Answer 1

we know that

cos0=1

sin45=1/√2

sin30=1/2

sin90=1

cos45=1/√2

cos60=1/2

now put these value

(1+1/√2+1/2)(1-1/√2+1/2)

(2√2+2+√2 /2√2)(2√2-2+√2 /2√2)

(3√2+2/2√2)(3√2-2/2√2)

(36-4)/4×2

32/8

=4

I hope you understand