Cos^-1(12/13) =
tan^-1 x , then find x
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Given : Cos⁻¹(12/13) = tan⁻¹ x
To Find : x
Solution:
Cos⁻¹(12/13) = tan⁻¹ x
Cos⁻¹(12/13) = α
=> 12/13 = Cosα
tan α = Sinα / Cosα
=> tan α = (√1 - Cos²α )/ Cosα
=> tan α = (√1 - (12/13)² )/ (12/13)
=> tan α = (√13² - 12² )/12
=> tan α = (√169 - 144 )/12
=> tan α = (√25 )/12
=> tan α = 5/12
tan⁻¹ x = α
=> x = tan α
=> x = 5/12
x = 5/12
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