Math, asked by vijaykewale16, 11 months ago

cos^-1(cos 100pi/3) who has dare to solve this question​

Answers

Answered by Sharad001
60

Question :-

Find its vale

 \implies \large  { \cos}^{ - 1} ( \cos \frac{100 \pi}{3} ) \\

Answer :-

→ π/3

Explanation :-

We know that

range of cos function is -π <x< π

Hence we can't write it 100π/3 .

because it is not in range of cosine function.

hence now what can we do ,

so in this case we can write it,

 \implies \large  { \cos}^{ - 1}  \{ \cos(33 \pi +  \frac{ \pi}{3} ) \} \\   \\  \implies \:  { \cos}^{ - 1} ( \cos \frac{ \pi}{3} ) \\  \\  \implies \:   \frac{ \pi}{3}

Answered by anantsirohi19923
0

Answer:

2π/3

Step-by-step explanation:

cos^-1(cos 100π/3)

cos^-1(cos 33π + π/3)

33π + π/3 will become Negative

So According to ITF property

cos^-1(-cos π/3)

π - cos^-1(cos π/3)

π - π/3

2π/3.

Similar questions