cosθ/1-tanθ+sin^2θ/sinθ-cosθ = sinθ+cosθ
Answers
Answered by
0
Answer:
L.H.S: cosθ/1-tanθ + sin∧2θ / sinθ-cosθ
= cos∧2θ/ cosθ-sinθ - sin∧2θ / cosθ-sinθ
=cosΛ2θ-sinΛ2θ/cosθ-sinθ
=(cosθ+sinθ)(cosθ-sinθ)/(cosθ-sinθ)
=(cosθ+sinθ)
Hence proved
Step-by-step explanation:
Similar questions