Math, asked by chowc780, 11 months ago

Cos 10A+Cos 8A + 3Cos 4A + 3 Cos 2A = 8 Cos A Cos³ 3A​

Answers

Answered by Anonymous
1

Step-by-step explanation:

2Cos9A*CosA + 3 (2Cos3A*CosA)

2CosA(Cos9A + 3Cos3A)

2CosA(Cos9A + Cos3A + 2Cos3A)

2CosA(2Cos6A*Cos3A + 2Cos3A)

4CosA*Cos3A(Cos6A+1)

4CosA*Cos3A{Cos2(3A) + 1}

4CosA*Cos3A{2Cos²(3A) - 1 + 1}

8CosA*Cos³3A

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