Math, asked by journeyburke4904, 9 months ago

Cos 11π/6 + tan (-7π/6) + sec π/3

Answers

Answered by AlluringNightingale
0

Answer:

(√3 + 12)/6

Solution:

Here ,

We need to find the value of ;

cos(11π/6) + tan(-7π/6) + sec(π/3)

Thus,

Here we go ↓

=> cos(11π/6) + tan(-7π/6) + sec(π/3)

=> cos(11π/6) - tan(7π/6) + sec(π/3)

=> cos(2π - π/6) - tan(π + π/6) + sec(π/3)

=> cos(π/6) - tan(π/6) + sec(π/3)

=> √3/2 - 1/√3 + 2

=> √3/2 - √3/3 + 2

=> (3√3 - 2√3 + 12)/6

=> (√3 + 12)/6

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