Cos 11π/6 + tan (-7π/6) + sec π/3
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Answer:
(√3 + 12)/6
Solution:
Here ,
We need to find the value of ;
cos(11π/6) + tan(-7π/6) + sec(π/3)
Thus,
Here we go ↓
=> cos(11π/6) + tan(-7π/6) + sec(π/3)
=> cos(11π/6) - tan(7π/6) + sec(π/3)
=> cos(2π - π/6) - tan(π + π/6) + sec(π/3)
=> cos(π/6) - tan(π/6) + sec(π/3)
=> √3/2 - 1/√3 + 2
=> √3/2 - √3/3 + 2
=> (3√3 - 2√3 + 12)/6
=> (√3 + 12)/6
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