Question

COS = 12/13 and sin 0 = 5/13,
therefore tan 0 =
*
O 13/5
05/12
O13/12
O 12/5​

Answer 1

Question:-

COS θ= 12/13 and sin θ = 5/13,

therefore tan θ =

a) 13/5

b) 5/12

c) 13/12

d) 12/5

Answer:-

• The value of tan θ= 5/12.

Solution:-

As given,

$\cos \theta = \frac{12}{13}$

$\sin \theta = \frac{5}{13}$

We know,

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {\boxed { \tan \theta = \frac{ \sin \theta}{ \cos \theta}}}$

Thus,

$\large{ \tt : \implies \: \: \: \tan \theta = \frac{5}{13} \div \frac{12}{13} }$

$\large{ \tt : \implies \: \: \: \tan \theta \: = \frac{5}{13} \times \frac{13}{12} }$

$\large{ \tt : \implies \: \: \: \tan \theta = \frac{5}{12} }$

• The value of tan θ= 5/12.

The correct option is (b)

Answer 2

Given

⠀

$\tt\longmapsto{cosθ = \dfrac{12}{13}}$

⠀

$\tt\longmapsto{sinθ = \dfrac{5}{13}}$

⠀

To find

⠀

$\tt\longmapsto{The\: value\: of\: tanθ.}$

⠀

Solution

⠀

★ We know that

⠀

$\: \: \: \: \: \: \: \: \: \: \: \: \boxed{\tt{\bigstar{tanθ = \dfrac{sinθ}{cosθ}{\bigstar}}}}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {tanθ = \dfrac{\dfrac{5}{13}}{\dfrac{12}{13}}}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {tanθ = \dfrac{\dfrac{5}{\cancel{13}}}{\dfrac{12}{\cancel{13}}}}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {tanθ = \dfrac{5}{12}}$

⠀

Hence,

$\tt\longmapsto{The\: value\: tanθ\: is\: \dfrac{5}{12}}$.

• Option B is the correct option.

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