Question

cos 12 -sin 12 /cos 12 +sin 12 +sin 147/cos147? ans 1

Answer 1

Please see the attachment

Answer 2

Answer:

Sorry to tell but the answer is actually 0

Step-by-step explanation:

converting all cos terms into sin terms we get,

$\frac{sin78-sin12}{sin78+sin12} + tan(147)\\we~know~that~sinA-sinB=2*sin(A-B)/2)*(sin(A+B)/2)~and~sinA+B=2*sin(A+B)/2)*(sin(A-B)/2\\Therefore,\\\frac{2}{2}* \frac{sin33*cos45}{sin45*cos33}+tan(147) \\sin45=cos45\\= \frac{sin33}{cos33} +tan(147)\\=tan(33)+tan(147)\\tan(147)~can~be~written~as~tna(180-33)\\we~know~that~tan(180-theta)=tan(-theta)\\=tan(33)+tan(180-33)\\=tan(33)-tan(33)\\=0$

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