Math, asked by riyan96, 11 months ago

cos 15* =??????????.....?????????????????????????????????? ​

Answers

Answered by AbhijithPrakash
6

Answer:

\displaystyle\cos \left(15^{\circ \:}\right)=\frac{\sqrt{2+\sqrt{3}}}{2}\quad \begin{pmatrix}\mathrm{Decimal:}&0.96592\dots \end{pmatrix}

Step-by-step explanation:

\cos \left(15^{\circ \:}\right)

\displaystyle\gray{\mathrm{Write}\:\cos \left(15^{\circ \:}\right)\:\mathrm{as}\:\cos \left(\frac{30^{\circ \:}}{2}\right)}

\displaystyle=\cos \left(\frac{30^{\circ \:}}{2}\right)

\displaystyle\gray{\mathrm{Using\:the\:half\:angle\:identity}:\quad \cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos \left(x\right)}{2}}}

\displaystyle=\sqrt{\frac{1+\cos \left(30^{\circ \:}\right)}{2}}

\displaystyle\gray{\mathrm{Use\:the\:following\:trivial\:identity}:\quad \cos \left(30^{\circ \:}\right)=\frac{\sqrt{3}}{2}}

\displaystyle=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}

\displaystyle\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}

\displaystyle\gray{\frac{1+\frac{\sqrt{3}}{2}}{2}=\frac{2+\sqrt{3}}{4}}

\displaystyle=\sqrt{\frac{2+\sqrt{3}}{4}}

\displaystyle\gray{\mathrm{Apply\:radical\:rule\:}\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0}

\displaystyle=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}

\gray{\sqrt{4}=2}

\displaystyle=\frac{\sqrt{2+\sqrt{3}}}{2}

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