Question

cos(180°-A)+cos(180°+B)+cos(180°+c)-sin(90°+D​

Answer 1

The answer is 0.

Given,

ABCD is a cyclic quadrilateral

We know that,

The sum of the opposite angles of a cyclic quadrilateral is 180°,

⇒ A + C = 180

⇒ A = 180 - C

Similarly,

B + D = 180

⇒ D = 180 - B

cos (180±x) = - cos x

sin (90 - x) = cos x

Thus,

cos(180+A)+cos(180-B)+cos(180-C)-sin(90-D)

= cos(180+A)+cos(D)+cos(A)-sin(90-D)

= - cos A + cos D + cos A - cos D    

= 0.

Answer 2

Answer:

Answer is 0

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Explanation:

Explanation is given in the pic attached

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