Math, asked by shivanirajput, 1 year ago

cos-1bracket cos13paai upon 6 bracket close

Answers

Answered by drashti5
1

 \cos{ }^{ - 1} (\cos( \frac{13\pi}{6} )) \\  =  \cos^{ - 1} ( \cos(2\pi +  \frac{\pi}{6} ) ) \\  =  \cos {}^{ - 1}( \cos( \frac{\pi}{6} ) ) \\  =  \frac{\pi}{6}
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shivanirajput: thanks yar
Answered by mitesh6
0
cos−1(cos(613π​))=cos−1(cos(2π+6π​))=cos−1(cos(6π​))=6π​
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