Math, asked by farzanfarooq8462, 1 day ago

cos^2 20 degree +cos^2 70 degree / sin^2 59 degree + sin^2 31 degree

Answers

Answered by neerajjoshi305
0

Answer:

1

Step-by-step explanation:

1. cos^2 (90 -70) + cos^70/sin^2 59 +cos^2(90-59)

2. WKT, sin theta(90 - A) = cos theta

and cos theta(90 - A) = sin theta

sin ^2 20 +cos^2 70/sin^2 59 + cos^2 31

3. aab. yai divide mai ha to sin se sin Katega aur cos se cos. all right.

hamara answer 1/1 aayega

1 is the answer

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