(cos^2 25° + cos^2 65°) + cosec theta sec (90- theta) -cot theta tan (90-theta)
Answers
Answered by
64
Hay dear here is your answer....
{cos^2 25°+(cos65°)^2}+cosec^2 theta-cot^2 theta
=[cos^2 25°+{cos(90°-25°)}]+1
=cos^25°+sin^2 25°+1
=1+
=1+1 =2[ans.]
Hope it will help you
{cos^2 25°+(cos65°)^2}+cosec^2 theta-cot^2 theta
=[cos^2 25°+{cos(90°-25°)}]+1
=cos^25°+sin^2 25°+1
=1+
=1+1 =2[ans.]
Hope it will help you
Answered by
13
Answer:
Step-by-step explanation:
{cos^2 25°+(cos65°)^2}+cosec^2 theta-cot^2 theta
=[cos^2 25°+{cos(90°-25°)}]+1
=cos^25°+sin^2 25°+1
=1+
=1+1 =2[ans.]
Similar questions