cos^2(30+x)-sin^2(30+x)
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1
therefore
cos^2(30+x) -sin^2(30+x)
cos^2(30+x)-(1-cos^2(30+x)
cos^2(30+x)+cos^2(30+x)-1
2cos^2(30+x)-1
cos^2(30+x) -sin^2(30+x)
cos^2(30+x)-(1-cos^2(30+x)
cos^2(30+x)+cos^2(30+x)-1
2cos^2(30+x)-1
bpush2004:
But there is - between them
yes but it is right bow
now
Answered by
0
cos2theta formula is cos^2theta-sin^2theta.
Therefore, the answer to your question is Cos2(30+x)=cos(60+2x)
Therefore, the answer to your question is Cos2(30+x)=cos(60+2x)
please see write answere
Hey i wrote in the form of cos2theta. Can't you just write it in 2cos^2theta-1.
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