cos^2 π/4+sin^2(3π/4)+sin^2(5π/4)+sin^2(7π/4)=2 proof
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0
Answer:
sin
2
(2π/3)+cos
2
(5π/6)−tan
2
(3π/4)
=sin
2
(π−π/3)+cos
2
(π−π/6)−tan
2
(π−π/4)
=(sin(π/3))
2
+(−cos(π/6))
2
−(−tanπ/4)
2
⎣
⎢
⎢
⎡
sin(π−x)=sinx
cos(n−x)=−cosx
tan(π−x)=−tanx
⎦
⎥
⎥
⎤
=(
2
3
)
2
+(
2
−
3
)
2
−(−1)
2
=
4
3
+
4
3
−1
=
4
6
−1
=
4
2
=
2
1
∴sin
2
(2π/3)+cos
2
(5π/6)−tan
2
(3π/4)=1/2.
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Answer:
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