Question

cos^2(π/6 + x) - sin^2(π/6 - x)

a. 1/2 cos2x
b. 0
c. -1/2 cos2x
d. 1/2​

Answer 1

Answer:

a

Step-by-step explanation:

cos^2A-sin^2B

cos(A+B)cos(A-B)

cos(π/6+x+π/6-x)cos(π/6+x-π/6+x)

cos(π/3)cos2x

1/2cos2x