Question

cos^2 60º + sec^2 30º + tan^2 45º​

Answer 1

★FIND:

➾$\bold{cos^2 60+ sec^2 30+ tan^2 45=?}$

★GIVEN:

⟶$\bold{cos^2 60 + sec^2 30+ tan^2 45}$

★SOLUTION:

☞$\bold{W.K.T}$

$\bold{Cos60=1/2,}$ $\bold{}$ $\bold{sec30 = \frac{2}{ \sqrt{3}}}$ ,$\bold{Tan45=1}$

☞$\bold{NOW,}$

➯$\bold{cos^2 60 + sec^2 30+ tan^2 45}$

➯$\bold{(1/2)^2+(2/\sqrt{3})^2+(1)^2}$

➯$\bold{(1/4)+(4/3)+1}$

➯$\bold{3/12+16/12+12/12}$

➯$\bold{ \frac{3+16+12}{12} }$

➯$\bold{31/12}$

Answer 2

Answer:

FIND:

➾\bold{cos^2 60+ sec^2 30+ tan^2 45=?}cos

2

60+sec

2

30+tan

2

45=?

★GIVEN:

⟶\bold{cos^2 60 + sec^2 30+ tan^2 45}cos

2

60+sec

2

30+tan

2

45

★SOLUTION:

☞\bold{W.K.T}W.K.T

\bold{Cos60=1/2,}Cos60=1/2, \bold{} \bold{sec30 = \frac{2}{ \sqrt{3}}}sec30=

3

2

,\bold{Tan45=1}Tan45=1

☞\bold{NOW,}NOW,

➯\bold{cos^2 60 + sec^2 30+ tan^2 45}cos

2

60+sec

2

30+tan

2

45

➯\bold{(1/2)^2+(2/\sqrt{3})^2+(1)^2}(1/2)

2

+(2/

3

)

2

+(1)

2

➯\bold{(1/4)+(4/3)+1}(1/4)+(4/3)+1

➯\bold{3/12+16/12+12/12}3/12+16/12+12/12

➯\bold{ \frac{3+16+12}{12} }

12

3+16+12

➯\bold{31/12}31/12