Math, asked by sbmbht22kgp, 1 year ago

Cos^2 90°+cosec^2 90°- cot^2 45°=?

Answers

Answered by aanshika69
1

Answer:

0

Step-by-step explanation:

  1. cos 90° is 0 than its square will also 0.
  2. cosec 90° is 1 than its square is 1
  3. cot 45° is 1 than square is 1.

0+1-1 = 0

Answered by Anonymous
1

Answer:

the answer is zero

Step-by-step explanation:

cos^2 90°+cosec^2 90° - cot^2 45°

0+1-1

o

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