Question

cos 2 A/ 1-sin 2A = 1+tan A/1-tan A​

Answer 1

hi friend

(1+tan A)/(1-tan A)

=(1+sinA/cos A)/(1-sinA/cos A)

=[(cos A+ sin A)/cos A ]/[cos A-sin A)/cos A]

=(cos A +sin A)/(cos A-sin A)

multiply numerator and denominator with  cos A-sinA

=(cos²A-sin²A)/(cos A-sin A)²

=cos 2A/cos²A+sin²A-2sinA.cos A

=cos 2A/1-sin2A

hope it helps you

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