cos 2 A/ 1-sin 2A = 1+tan A/1-tan A
Answers
Answered by
2
hi friend
(1+tan A)/(1-tan A)
=(1+sinA/cos A)/(1-sinA/cos A)
=[(cos A+ sin A)/cos A ]/[cos A-sin A)/cos A]
=(cos A +sin A)/(cos A-sin A)
multiply numerator and denominator with cos A-sinA
=(cos²A-sin²A)/(cos A-sin A)²
=cos 2A/cos²A+sin²A-2sinA.cos A
=cos 2A/1-sin2A
hope it helps you
mark me as the brainliest
Similar questions